a) Ta có: \(\left|x\right|+\left|x+1\right|+\left|x+2\right|+\left|x+3\right|\ge0\) ( do mỗi số hạng \(\ge0\)
\(\Rightarrow6x\ge0\)
\(\Rightarrow x\ge0\)
b) Vì \(x\ge0\)
\(\Rightarrow x+x+1+x+2+x+3=6x\)
\(\Rightarrow4x+6=6x\)
\(\Rightarrow2x=6\)
\(\Rightarrow x=3\)
Vậy x = 3
Chứng minh rằng :
a)\(\dfrac{1}{x}\)-\(\dfrac{1}{x+a}=\dfrac{a}{x\left(x+a\right)}\)
b)\(\dfrac{1}{x\left(x+1\right)}-\dfrac{1}{\left(x+1\right)\left(x+2\right)}=\dfrac{2}{x\left(x+1\right)\left(x+2\right)}\)
c)\(\dfrac{1}{x\left(x+1\right)\left(x+2\right)}-\dfrac{1}{\left(x+1\right)\left(x+2\right)\left(x+3\right)}=\dfrac{3}{x\left(x+1\right)\left(x+2\right)\left(x+3\right)}\)
Tìm x:
a,\(x^2\) - 9 = 0
b,\(\left(x-3\right)^2-25=0\)
c,\(\left(x-3\right)\left(2x-5\right)=0\)
d,\(\left(x-3\right)\cdot x-2\left(x-3\right)=0\)
e,\(3x\left(x-1\right)-5\left(1-x\right)=0\)
g,\(x^2+6x-7=0\)
h,\(2x^2+5x-7=0\)
Tìm x
a, \(311-x+82=46+\left(x-21\right)\)
b,\(-\left(x-3+85\right)=\left(x+70-71\right)-5\)
c,\(-2\left(x+6\right)+6\left(x-10\right)=8\)
d,\(\left|x\right|=41\)
e, \(\left|-8\right|.\left|x\right|=\left|-56\right|\)
f,\(3.\left|x-2\right|+2x=19\) với \(x\) \(\ge\) 2
Giúp hộ đi ạ, cảm ơn.
Tìm STN x biết rằng:
a)\(720:[41-\left(2x-5\right)]=2^3\cdot5\)
b)\(\left(x+1\right)+\left(x+2\right)+\left(x+3\right)+...+\left(x+100\right)=5+50\)
d)\(\left(x+3\right)^{10}=\left(x-3\right)^{17}\)
1) Tìm x;y thuộc Z thỏa :
\(\left(x-2\right)^2+\left(y+16\right)^{2016}=0\)
1.Tìm x,y
a)\(\left|x\right|\)=2017
b)\(\left|x\right|\)=\(\left|2017\right|\)
c)\(\left|x\right|\)+\(\left|y\right|\)=0
d)\(\left|x+5\right|\)+\(\left|y-3\right|\)=0
f)\(\left|x+2\right|\)=\(-5\)
Bài 1; Tìm x, biết:
a) \(\text{2. |4 - x| = |-8|}\)
b) \(\left(x-1^2\right)=0\)
c) \(x\left(x-1\right)=0\)
d) \(\left(x+1\right)\left(x-2\right)=0\)
Tìm x, biết:
\(\dfrac{2}{\left(x-1\right)\left(x-3\right)}+\dfrac{5}{\left(x-3\right)\left(x-8\right)}+\dfrac{12}{\left(x-8\right)\left(x-20\right)}-\dfrac{1}{x-20}=\dfrac{-1}{4}\)
