a) \(n_{H_2SO_4}=\dfrac{200.10\%}{98}=\dfrac{10}{49}\left(mol\right)\)
PTHH: Zn + H2SO4 --> ZnSO4 + H2
\(\dfrac{10}{49}\)------>\(\dfrac{10}{49}\)--->\(\dfrac{10}{49}\)
=> \(V_{H_2}=\dfrac{10}{49}.22,4=\dfrac{32}{7}\left(l\right)\)
b) \(n_{ZnSO_4}=\dfrac{10}{49}\left(mol\right)\)