\(n_{H_2}=\frac{5,6}{22,4}=0,25\left(mol\right)\)
\(Zn+2HCl\rightarrow ZnCl_2+H_2\)
Theo PTHH:
\(n_{Zn}=n_{H_2}=0,25\left(mol\right)\Rightarrow m_{Zn}=0,25.65=16,25\left(g\right)\)
\(n_{HCl}=2n_{H_2}=2.0,25=0,5\left(mol\right)\Rightarrow m_{HCl}=0,5.36,5=18,25\left(g\right)\)
\(n_{ZnCl_2}=n_{H_2}=0,25\left(mol\right)\Rightarrow m_{ZnCl_2}=0,25.136=34\left(g\right)\)