Công thức chung: CnH2n+2
\(d_{Ankan/kk}=1,155155\)
\(\Rightarrow M_{Ankan}=33,499495\)
\(\Leftrightarrow14n+2=33,499495\)
\(\Leftrightarrow n=2,25\)
2 Ankan là C2H6 và C3H8
Ta có :
\(\overline{M_{Ankan}}=33,499495\)
\(\Leftrightarrow\frac{30n_{C2H6}+44n_{C3H8}}{n_{C2H6}+n_{C3H8}}=33,499495\)
\(\Leftrightarrow-3,5n_{C2H6}=-10,5nC_3H_8\)
\(\Leftrightarrow\frac{n_{C2H6}}{n_{C3H8}}=3\)
\(\Rightarrow V\%_{C2H6}=n\%_{C2H6}=\frac{3}{4}.100\%=75\%\)
\(\Rightarrow\%V_{C3H8}=100\%-75\%=25\%\)