Qua O kẻ Om//a
=> \(\widehat{A_1}\)=\(\widehat{O_1}\)(SLT)
=>\(\widehat{O_1}\)=\(30^o\)
a//b; Om//a=>Om//b
=>\(\widehat{O_2}\)=\(\widehat{B_1}\)(SLT)
=>\(\widehat{O_2}\)=\(45^o\)
Có:\(\widehat{O_1}\)+\(\widehat{O_2}\)=\(\widehat{AOB}\)
\(30^o\)+\(45^o\)=\(\widehat{AOB}\)
\(75^o\)=\(\widehat{AOB}\)
Vậy\(\widehat{AOB}\)= \(75^o\)



