\(AH=HB=\dfrac{a}{2}\).
\(DH=\sqrt{\left(a\sqrt{3}\right)^2+\left(\dfrac{a}{2}\right)^2}=\dfrac{\sqrt{13}a}{2}\).
\(SH=DH.tan\widehat{SDH}=\dfrac{\sqrt{13}a}{2}.tan60^o=\dfrac{\sqrt{39}a}{2}\).
Thể tích khối chóp S.ABCD là: \(\dfrac{1}{3}.SH.S_{ABCD}=\dfrac{1}{3}.\dfrac{\sqrt{39}a}{2}.a.\sqrt{3}a=\dfrac{\sqrt{13}a^3}{2}\).