Ta có : \(\widehat{xOy}+\widehat{yOt}=180\) ( kề bù )
\(150^0+\widehat{yOt}=180\)
\(\Rightarrow\widehat{yOt}=180^0-150^0\)
\(\Rightarrow\widehat{yOt}=30^0\)
Vậy \(\widehat{yOt}=30^0\)
Theo đề bài có: \(\widehat{xOy}+\widehat{yOt}=180^o\) (kề bù)
\(\Rightarrow150^o+\widehat{yOt}=180^o\)
\(\Rightarrow\widehat{yOt}=180^o-150^o\)
\(\Rightarrow\widehat{yOt}=30^o\)