Vì \(\text{2x=3y}\) và \(x+3y=3\)
\(\Rightarrow x+2x=3\)
\(\Rightarrow3x=3\)
\(\Rightarrow x=1\)
\(\Rightarrow2.1=3y\)
\(\Rightarrow2=3y\)
\(\Rightarrow y=\dfrac{2}{3}\)
\(\dfrac{3}{4}\cdot x^6\cdot y^5=\dfrac{3}{4}\cdot1^6\cdot\left(\dfrac{2}{3}\right)^5=\dfrac{3}{4}\cdot\dfrac{32}{243}\cdot1=\dfrac{8}{81}\)
Vậy ........