a) Vì \(OA\perp OM\left(gt\right)\)
=> \(\widehat{AOM}=90^0.\)
Vì \(OB\perp ON\left(gt\right)\)
=> \(\widehat{BON}=90^0.\)
b) Ta có:
\(\left\{{}\begin{matrix}\widehat{AON}+\widehat{MON}=\widehat{AOM}\left(gt\right)\\\widehat{BOM}+\widehat{MON}=\widehat{BON}\left(gt\right)\end{matrix}\right.\)
Mà \(\widehat{AOM}=\widehat{BON}\left(=90^0\right).\)
\(\Rightarrow\widehat{AON}+\widehat{MON}=\widehat{BOM}+\widehat{MON}\)
=> \(\widehat{AON}=\widehat{BOM}.\)
Hay \(\widehat{NOA}=\widehat{MOB}\left(đpcm\right).\)
Chúc bạn học tốt!
