Ta có: \(n_{H_2SO_4}=0,5.\dfrac{300}{1000}=0,15\left(mol\right)\)
\(PTHH:2Al+3H_2SO_4--->Al_2\left(SO_4\right)_3+3H_2\)
Theo PT: \(n_{Al}=\dfrac{2}{3}.n_{H_2SO_4}=\dfrac{2}{3}.0,15=0,1\left(mol\right)\)
\(\Rightarrow a=0,1.27=2,7\left(g\right)\)
Theo PT: \(n_{H_2}=n_{H_2SO_4}=0,15\left(mol\right)\)
\(\Rightarrow V_{H_2}=0,15.22,4=3,36\left(lít\right)\)
\(2Al+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+3H_2\)
\(n_{H2SO4_{ }}=0,3.0,5=0,15mol\)
\(\rightarrow n_{Al}=0,1mol\)
\(\rightarrow m_{Al}=0,1.27=2,7g\)
\(V_{H2}=0,15.22,4=3,36l\)