TH1 : a<b
\(\Rightarrow am< bm\)
\(\Rightarrow ab+am< ab+bm\Rightarrow a\left(b+m\right)< b\left(a+m\right)\)
\(\Rightarrow\frac{a}{b}< \frac{a+m}{b+m}\)
TH2 : a=b
\(\Rightarrow am=bm\)
\(\Rightarrow ab+am=ab+bm\Rightarrow a\left(b+m\right)=b\left(a+m\right)\)
\(\Rightarrow\frac{a}{b}=\frac{a+m}{b+m}\)
TH1 : a>b
\(\Rightarrow am>bm\)
\(\Rightarrow ab+am>ab+bm\Rightarrow a\left(b+m\right)>b\left(a+m\right)\)
\(\Rightarrow\frac{a}{b}>\frac{a+m}{b+m}\)
Vậy ... ( có 3 trường hợp )