Question

Cho △ABC = △MNP biết A^; B^; C^ = 3; 4; 5. Tính góc △MNP

Answer 1

Lời giải:
Ta có:

$\frac{\widehat{A}}{3}=\frac{\widehat{B}}{4}=\frac{\widehat{C}}{5}=\frac{\widehat{A}+\widehat{B}+\widehat{C}}{3+4+5}=\frac{180^0}{12}=15^0$

$\Rightarorw \widehat{A}=3.15^0=45^0; \widehat{B}=4.15^0=60^0; \widehat{C}=5.15^0=75^0$

Vì $\triangle ABC=\triangle MNP$ nên:

$\widehat{M}=\widehat{A}=45^0$

$\widehat{N}=\widehat{B}=60^0$

$\widehat{P}=\widehat{C}=75^0$