\(\widehat{C}=70^o\Rightarrow\widehat{BCI}=\widehat{ICA}=\dfrac{70^o}{2}=35^o\)
Xét ΔBIC ta có:
\(\widehat{B}+\widehat{I}+\widehat{C}=180^o\\ \widehat{B}+120^o+35^o=180^o\\ \widehat{B}=25^o\\ \widehat{IBC}=\dfrac{\widehat{B}}{2}=25^o\Rightarrow\widehat{B}=50^o\)
Xét ΔABC ta có:
\(\widehat{A}+\widehat{B}+\widehat{C}=180^o\\ \widehat{A}+50^o+70^o=180^o\\ \widehat{A}=60^o\\ \)