Ta có:
\(a^2+b^2+c^2+d^2=\left(b+c+d\right)^2+b^2+c^2+d^2\)
\(=2\left(b^2+c^2+d^2\right)+2\left(bd+cd+bc\right)\)
\(=\left(b^2+2bc+c^2\right)+\left(c^2+2cd+d^2\right)+\left(d^2+2db+b^2\right)\)
\(=\left(b+c\right)^2+\left(c+d\right)^2+\left(d+b\right)^2\)