Lời giải:
\(a+b=9\Rightarrow 2a+9=2a+(a+b)=3a+b\)
\(\Rightarrow \frac{6a+2b}{2a+9}=\frac{6a+2b}{3a+b}=\frac{2(3a+b)}{3a+b}=2(1)\)
\(a+b=9\Rightarrow b=9-a\Rightarrow -3a-b=-3a-(9-b)=-2a-9\)
\(\Rightarrow \frac{-3a-b}{-2a-9}=\frac{-2a-9}{-2a-9}=1(2)\)
Từ \((1);(2)\Rightarrow A=\frac{6a+2b}{2a+9}+\frac{-3a-b}{-2a-9}=2+1=3\)