a) A \(=\dfrac{5}{x+2}\) là phân số \(\Leftrightarrow x+2\in Z\Leftrightarrow x\in Z\)
Vậy để A là phân số : x\(\in\) Z
b) A = \(\dfrac{-1}{2}\)\(\Leftrightarrow\dfrac{5}{x+2}=\dfrac{-1}{2}\)
\(\Leftrightarrow2.5=-1\left(x+2\right)\)
\(\Leftrightarrow10=-x-2\)
\(\Leftrightarrow10+2=-x\)
\(\Leftrightarrow12=-x\)
\(\Leftrightarrow x=-12\)
Vậy để \(A=\dfrac{-1}{2}\)thì x = -12
c) \(A\in Z\Leftrightarrow\dfrac{5}{x+2}\in Z\)
\(\Leftrightarrow x+2\inƯ\left(5\right)=\left\{-5;-1;1;5\right\}\)
\(\Leftrightarrow x\in\left\{-7;-3;-1;3\right\}\)
Vậy để A là số nguyên thì \(x\in\left\{-7;-3;-1;3\right\}\)