ta có : A=1-\(\frac{1}{2}\)+\(\frac{1}{3}-\frac{1}{4}+\frac{1}{5}-\frac{1}{6}+...+\frac{1}{149}-\frac{1}{150}\)(1)
=1\(\frac{1}{2}+\frac{1}{3.4}+\frac{1}{5.6}+....+\frac{1}{149.150}\)
từ (1) \(\Rightarrow\)1-\(\frac{1}{150}\)=\(\frac{14}{15}\)
b) chưa biết............