nZn= 6.5/65 = 0.1 mol
nH2SO4 = 0.2 mol
Zn + H2SO4 --> ZnSO4 + H2
Bđ: 0.1___0.2
Pư: 0.1___0.1_______0.1_____0.1
Kt: 0____0.1_______0.1______0.1
Từ PTHH ta thấy : H2SO4 dư
mH2SO4 dư = 0.1*98=9.8g
mZnSO4 = 0.1 * 161=16.1g
CM ZnSO4 = 0.1/0.2 = 0.5M
CM H2SO4 dư = 0.1/0.2=0.5 M