Nếu tớ làm sai gì mấy bạn góp ý giúp tớ nhé ^^!
a) \(MgCO_3+HCl\rightarrow MgCl+HCO_3\)
b) \(m_{tapchat}=\dfrac{60\cdot10}{100}=6\left(g\right)\)
\(m_{MgCO_3}=60-6=54\left(g\right)\rightarrow n_{MgCO_3}=\dfrac{54}{84}\sim0,64\left(mol\right)\)
\(\rightarrow n_{HCl}=0,64\left(mol\right)\rightarrow m_{HCl_{pư}}=0,64\cdot36,5=23,36\left(g\right)\)
\(\rightarrow m_{HCl}=\dfrac{23,36\cdot100}{20}=116,8\left(g\right)\)
c) \(n_{MgCl}=n_{MgCO_3}=0,64\left(mol\right)\)
\(\rightarrow m_{MgCl}=0,64\cdot\left(24+35,5\right)=38,08\left(g\right)\)
\(m_{dd}=60+116,8=176,8\left(g\right)\)
\(C_{\%_{dd}}=\dfrac{38,08}{176,8}\sim0,2\%\)
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