nCu = 60/64 = 0.9375 mol
mAgNO3 = 200*17/100=34g
nAgNO3 = 34/170=0.2 mol
Cu + 2AgNO3 --> Cu(NO3)2 + 2Ag
Bđ: 0.9375__0.2
Pư: 0.1______0.2_______0.1_______0.2
Pư: 0.8375___0________0.1_______0.2
mCr = mCu dư + mAg = 0.8375*64 + 0.2*108 = 75.2g
mdd sau phản ứng = 60 + 200 - 75.2 = 184.8 g
mCu(NO3)2 = 0.1*188=18.8g
C%Cu(NO3)2 = 10.17%