\(n_{Na}=\frac{4,6}{23}=0,2\left(mol\right)\)
\(n_S=\frac{4,6}{32}=0,14\left(mol\right)\)
\(2Na+S\rightarrow Na_2S\)
0,2_________0,1
\(Na_2S+2HCl\rightarrow2NaCl+H_2S\)
0,1 _____________________0,1
\(\Rightarrow V_{H2S}=0,1.22,4=2,24\left(l\right)\)