nhh(CO2 ; SO2) = \(\dfrac{3,36}{22,4}\) = 0,15mol
CO2 + Ca(OH)2 -> CaCO3 + H2O
x------------------->x
SO2 + Ca(OH)2 -> CaSO3 + H2O
y------------------->y
ta có : \(\left\{{}\begin{matrix}x+y=0,15\\100x+120y=17\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=0,05mol\\y=0,1mol\end{matrix}\right.\)
=>VCO2 = 0,05.22,4 = 1,12 (l)
=>VSO2 = 3,36 - 1,12 = 2,24 (l)