nC2H5OH=92/46=2mol
nCH3C00H=30/60=0.5mol
------------------C2H5OH+CH3C00H(H2S04 đặc)<=>CH3C00C2H5+H20
Trước pư----2----------->0.5(mol)
Pứng----------0.5-------->0.5(mol)----...
Sau pư-------1.5--------->0
=>C2H5OH dư 1.5mol
=>nCH3C00C2H5=0.5mol
=>mCH3C00C2H5=0.5*88=44(g)