Ta có : \(\frac{2a}{3}=\frac{b}{2}=\frac{c}{-4}=\frac{d}{5}\)
\(\Rightarrow\frac{a}{\frac{3}{2}}=\frac{b}{2}=\frac{c}{-4}=\frac{d}{5}=\frac{3a}{\frac{9}{2}}=\frac{2b}{4}=\frac{4c}{-16}=\frac{3a-2b+4c-d}{\frac{9}{2}-4+\left(-16\right)-5}=\frac{2}{-20,5}\)
\(\Rightarrow a=-\frac{6}{41};b=-\frac{8}{41};c=82;d=-102,5\)
Khi đó dễ dàng tính được a + b - 2c - 3d