a) Zn+2HCl--->ZnCl2+H2
x-------------------x(mol)
Fe+2HCl--->FeCl2+H2
y----------------y(mol)
muối la ZnCl2 và FeCl2
\(\left\{{}\begin{matrix}65x+56y=2,98\\136x+127y=6,53\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=0,02\\y=0,03\end{matrix}\right.\)
% m Zn=0,02.65/2,98.100%=43,62%
%m Fe=1000-43,62=56,38%
b) n HCl=2 n KL=0,05.2=0,1(mol)
CM HCl=0,1/0,1=1(M)
Theo bài ra ta có hpt