\(CaO+H_2O\rightarrow Ca\left(OH\right)_2\)
56(kg)__________74(kg)
252(kg)_________m(g)
mCaO = 280 - 10%.280 = 252 (kg)
a) \(m_{Ca\left(OH\right)_2TT}=333.85\%=283,05\left(kg\right)\)
b) \(Ca\left(OH\right)_2+2HCl\rightarrow CaCl_2+2H_2O\)
__74(kg)________________111(kg)
__283,05(kg)_____________x(kg)
\(\Rightarrow x=424,575\left(kg\right)\)