nCO2 = 2.24/22.4 = 0.1 mol
CaCO3 + H2SO4 --> CaSO4 + CO2 + H2O
0.1_______0.1_______0.1_____0.1
mCaO = 21.2 - 0.1*100 = 11.2 g
%CaCO3 = 47.17%
%CaO = 52.83%
nCaO = 0.2 mol
CaO + H2SO4 --> CaSO4 + H2O
0.2_____0.2_______0.2
mH2SO4 = 29.4 g
mdd H2SO4 = 300 g
mdd sau phản ứng = 21.2 + 300 - 4.4 = 316.8 g
mCaSO4 = 40.8 g
C%CaSO4 = 40.8/316.8*100% = 12.88%