nCa(OH)2 = 0.15 mol
nHCl = 0.2 mol
Ca(OH)2 + 2HCl --> CaCl2 + 2H2O
Bđ: __0.15_____0.2
Pư: __0.1______0.2______0.1
Kt: __0.05______0_______0.1
CM Ca(OH)2 dư = 0.05/0.5 = 0.1M
CM CaCl2 = 0.1/(0.2 + 0.3) = 0.2M
Ca(OH)2 + CO2 --> CaCO3 + H2O
0.05_______________0.05
mCaCO3 = 0.05*100 = 5 g