\(m_{HCl}=\dfrac{C_{\%}.m_{dd}}{100\%}=\dfrac{7,3.150}{100\%}=10,95\left(g\right)\)
\(\Rightarrow n_{HCl}=\dfrac{m}{M}=\dfrac{10,95}{36,5}=0,3\left(mol\right)\)
\(RO+2HCl\rightarrow RCl_2+H_2\)
Theo PTHH : \(n_{RO}=\dfrac{1}{2}.n_{HCl}=\dfrac{1}{2}.0,3=0,15\left(mol\right)\)
\(\Rightarrow M_{RO}=\dfrac{m}{n}=\dfrac{12}{0,15}=80\left(g/mol\right)\)
\(\Rightarrow M_R=80-16=64\left(g/mol\right)\)
=> R là nguyên tố Cu
CTHH : CuO
\(CuO+2HCl\rightarrow CuCl_2+H_2\)
Theo PTHH : \(n_{CuCl_2}=\dfrac{1}{2}.n_{HCl}=\dfrac{1}{2}.0,3=0,15\left(mol\right)\)
\(\Rightarrow m_{CuCl_2}=n.M=0,15.135=20,25\left(g\right)\)
Theo PTHH : \(n_{H_2}=n_{CuCl_2}=0,15\left(mol\right)\)
\(\Rightarrow m_{H_2}=n.M=0,15.2=0,3\left(g\right)\)
Theo ĐLBTKL :
\(m_{ddCuCl_2}=m_{Cu}+m_{HCl}-m_{H_2}\)
\(=12+150-0,3=161,7\left(g\right)\)
\(C_{\%CuCl_2}=\dfrac{20,25}{161,7}.100\%=12,5\%\)
