a. Fe+2HCl---->FeCl2+H2
FeO+2HCl---->FeCl2+H2O
b. theo phương trình khí sinh ra là H2=>nH2=\(\dfrac{2.24}{22.4}\) =0.1(mol)
Fe+2HCl--->FeCl2+H2
mol: 0.1<---0.2<-----------0.1(mol)
mFe=56*0.1=5.6(g)
mFeO=12.8-5.6=7.2(g)
c. nFeO=\(\dfrac{7.2}{72}\)=0.1(mol)
FeO+2HCl---->FeCl2+H2O
mol:0.1--->0.2 (mol)
nHCl=0.2+0.2=0.4(mol)
VHCl=\(\dfrac{0.4}{2}\)=0.2(l)