\(n_{Fe}=0,2\left(mol\right)\)
\(n_S=0,3\left(mol\right)\)
\(Fe+S-t^0->FeS\)
\(\dfrac{0,2}{1}< \dfrac{0,3}{1}\) => S dư
\(2FeS+10H_2SO_4\left(đ\right)-t^0->Fe_2\left(SO_4\right)_3+9SO_2+10H_2O\)
0,2...............1..................................0,1...................0,9
\(m=m_{ddH_2SO_4}=\dfrac{1.98.100\%}{98\%}=100\left(g\right)\)
\(V_{SO_2}=20,16\left(l\right)\)
b) \(Fe_2\left(SO_4\right)_3+3Ba\left(OH\right)_2-->2Fe\left(OH\right)_3\downarrow+3BaSO_4\downarrow\)
0,1..........................................................0,2
\(2Fe\left(OH\right)_3-t^0->Fe_2O_3+3H_2O\)
0,2...............................0,1
\(m_{Fe_2O_3}=0,1.160=16\left(g\right)\)
