\(a.n_{Cu}=\dfrac{m}{M}=\dfrac{1,08}{64}=0,016875\left(mol\right)\)
\(PTHH:2Al+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+3H_2\)
\(\Rightarrow n_{H_2SO_4}=n_{H_2}=\dfrac{3}{2}n_{Al}=1,5.0,016875=0,0253125\left(mol\right)\)
\(\Rightarrow m_{H_2SO_4}=n.M=0,0253125.98=2,480625\left(g\right)\)
\(b.V_{H_2}=n.22,4=0,0253125.22,4=0,567\left(l\right)\)