\(n_{Al}=\dfrac{10,8}{27}=0,4\left(mol\right)\)
a) Pt : \(2Al+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+3H_2|\)
2 3 1 3
0,4 0,6 0,2 0,6
\(n_{H2}=\dfrac{0,4.3}{2}=0,6\left(mol\right)\)
\(V_{H2\left(dktc\right)}=0,6.22,4=13,44\left(l\right)\)
b) \(n_{H2SO4}=\dfrac{0,4.3}{2}=0,6\left(mol\right)\)
⇒ \(m_{H2SO4}=0,6.98=58,8\left(g\right)\)
\(C_{ddH2SO4}=\dfrac{58,8.100}{189,2}=31,08\)0/0
c) \(n_{Al2\left(SO4\right)3}=\dfrac{0,6.1}{3}=0,2\left(mol\right)\)
⇒ \(m_{Al2\left(SO4\right)3}=0,2.342=68,4\left(g\right)\)
\(m_{ddspu}=10,8+189,2-\left(0,6.2\right)=198,8\left(g\right)\)
\(C_{Al2\left(SO4\right)3}=\dfrac{68,4.100}{198,8}=34,41\)0/0
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