\(n_{H2S}=0,1\left(mol\right)\)
\(n_{NaOH}=0,08\left(mol\right)\)
\(\Rightarrow\frac{n_{NaOH}}{n_{SO2}}=0,8\)
\(\Rightarrow\) Chỉ tạo NaHS
\(NaOH+H_2S\rightarrow NaHS+H_2O\)
\(\Rightarrow n_{NaHS}=0,08\left(mol\right)\)
\(\Rightarrow m_{NaHS}=0,08.56=4,48\left(g\right)\)