Ta có sơ đồ đường chéo:
\(\left\{{}\begin{matrix}\left[H^+\right]=2aM\\\left[OH^-\right]=0,15M\end{matrix}\right.\)\(\left[H^+\right]=0,01M\)\(\dfrac{0,15+0,01}{2a-0,01}\)=\(\dfrac{V_1}{V_2}\)=\(\dfrac{0,1}{0,15}\)
=> a = 0,125
=> p=nBaSO4= 0,00375.233=0,87375