Gọi công thức tổng quát là RCHO
\(PTHH:RCHO+2AgNO_3+3NH_3+H_2O\rightarrow RCOONH_4+NH_4NO_3+2Ag\)
Ta có:
\(n_{Ag}=\frac{3,24}{108}=0,03\left(mol\right)\Rightarrow n_{RCHO}=0,015\left(mol\right)\)
\(\Rightarrow M_{RCHO}=\frac{0,94}{0,015}=62,67\left(\frac{g}{mol}\right)\)
Vậy CTPT là C2H5CHO và C3H7CHO
Gọi \(\left\{{}\begin{matrix}n_{C2H5CHO}:x\left(mol\right)\\n_{C3H7CHO}:y\left(mol\right)\end{matrix}\right.\)
Giải hệ PT:
\(\left\{{}\begin{matrix}58x+72y=0,94\\x+y=0,015\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=0,01\\y=0,005\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}\%m_{C2H5CHO}=\frac{0,01.58}{0,94}.100\%=61,7\%\\\%m_{C3H7CHO}=100\%-61,7\%=38,3\%\end{matrix}\right.\)
