Đặt A=\(\sqrt{19+\sqrt{136}}-\sqrt{19-\sqrt{136}}\)
=> A^2=38-2\(\sqrt{\left(19+\sqrt{136}\right)\left(19-\sqrt{136}\right)}\)
=38-2\(\sqrt{19^2-136}\)
=38-2\(\sqrt{225}\)=38-30=8
B)B=3-4+2.5=9
B4:đặt \(\sqrt{x+5}=t\)
=>\(\sqrt{4t}-2\sqrt{t}+\sqrt{9t}\)=6
=>\(\sqrt{t}\)(2-2+3)=6
=>\(\sqrt{t}\)=6
=>t=36 tmđk