\(nCH_2=CH_2\rightarrow\left(t^o,xt,p\right)\left(-CH_2-CH_2-\right)_n\)
ĐL BTKL: \(m_{C_2H_4}=m_{polietilen}=5,6g\)
\(\Rightarrow m_{polietilen}=5,6.75\%=5,4g\)
\(m_{\left(-CH_2-CH_2-\right)_n}=m_{C_2H_4\left(pư\right)}=\dfrac{5,6.75}{100}=4,2\left(g\right)\)