Question

Cân = pt:

a)C_xH_y+O2->CO₂+H₂O

b)C_xH_yO_z+O₂->CO₂+H₂O

c)Fe_xO_y+CO->Fe+CO₂

d)Fe₃O₄+HCl->FeCl₂+FeCl₃+H₂O

Answer 1

a)C_xH_y+(x+\(\dfrac{y}{4}\))O₂->xCO₂+\(\dfrac{y}{2}\)H₂O

b)C_xH_yO_z+(x+\(\dfrac{y}{4}\)-\(\dfrac{z}{2}\))O₂->xCO₂+\(\dfrac{y}{2}\)H₂O

c)Fe_xO_y+yCO->xFe+yCO₂

d)Fe₃O₄+8HCl->FeCl₂+2FeCl₃+4H₂O

Answer 2

a)2C_xH_y+(4x+y)O₂->xCO₂+2yH₂O

b)C_xH_yO_z+(x+\(\dfrac{y}{4}\)-\(\dfrac{z}{2}\))O₂->xCO₂+\(\dfrac{y}{2}\)H₂O

c)Fe_xO_y+yCO->xFe+yCO₂

d)Fe₃O₄+8HCl->FeCl₂+2FeCl₃+4H₂O

Answer 3

a) \(2C_xH_y+\left(4y+x\right)O_2\rightarrow xCO_2+2yH_2O\)

b)\(C_xH_yO_z+\left(x+\dfrac{y}{4}-\dfrac{z}{2}\right)O_2\rightarrow xCO_2+\dfrac{y}{2}H_2O\)

c) \(Fe_xO_y+yCO\rightarrow xFe+yCO_2\)

d) Fe₃O₄ + 8HCl \(\rightarrow\) FeCl₂ + 2FeCl₃ + 4H₂O