Question

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Answer 1

2Al+3CuO -> Al₂O₃+3Cu

2Na+H₂O -> 2NaOH+H₂

 

Answer 2

\(a,2Al+3CuO\to Al_2O_3+3Cu\\ b,Na+H_2O\to NaOH+\dfrac{1}{2}H_2\\ c,Cu+2H_2SO_{4(đ)}\xrightarrow{t^o}CuSO_4+SO_2\uparrow+2H_2O\)

Answer 3

a,2Al+3CuO→Al2O3+3Cub,Na+H2O→NaOH+12H2c,Cu+2H2SO4(đ)to→CuSO4+SO2↑+2H2O

Answer 4

2Al+3CuO -> Al₂O₃+3Cu

2Na+H₂O -> 2NaOH+H₂