Question

Cần dùng bao nhiêu ml dung dịch H2SO4 0,5M để trung hòa 50gam dung dịch NaOh 10%

Answer 1

\(m_{NaOH}=\frac{50.10}{100}=5\left(g\right)\Rightarrow n_{NaOH}=\frac{5}{40}=0,125\left(mol\right)\)

\(PTHH:\text{ }H_2SO_4+2NaOH\rightarrow Na_2SO_4+2H_2O\)

\(Theo\text{ PT: }n_{H_2SO_4}=\frac{1}{2}n_{NaOH}=\frac{1}{2}.0,125=0,0625\left(mol\right)\)

\(Vdd_{H_2SO_4}=\frac{n_{H_2SO_4}}{C_M}=\frac{0,0625}{0,5}=0,125\left(l\right)=125\text{ }ml\)

Answer 2

\(m_{NaOH}=\frac{50.10}{100}\)=5 g

\(n_{NaOH}=\frac{5}{40}=0,125\left(mol\right)\)

PTHH: H₂SO₄+2NaOH\(\rightarrow\)Na₂SO₄+2H₂O

            0,0625   \(\leftarrow\)0,125( mol)

VẬY \(V_{H2SO4}=\frac{0,0625}{0,5}=0,125\left(l\right)\)

ta có: 1l=1000ml\(\Rightarrow\) 0,125(l)=125ml

chúc bạn học tốt like nha

Answer 3

nNaOH=\(\frac{50\cdot10}{100\cdot40}=0,125mol\)

PTHH:    H2SO4 + 2NaOH---->  Na2SO4 + 2H2o

Gọi V ddH2So4 là x(\(l\))----> nH2SO4=0,5x\(mol\)

 Theo PT : nH2SO4=1/2nNaOh-----> 0,5x=\(\frac{1}{2}\).0.125=0,0625

              ----> x=\(\frac{0,0625}{0,5}=0,125l\)l= 125 ml

                       Vậy VddH2SO4= 125ml