Question

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9³.8⁷/6⁹.16²

Nhớ là tính nhanh đấy nhé!

 

Answer 1

Ta có: \(\frac{9^3.8^7}{6^9.16^2}=\frac{\left(3^2\right)^3.\left(2^3\right)^7}{2^9.3^9.\left(2^4\right)^2}\)=\(\frac{3^6.2^{21}}{2^9.3^9.2^8}=\frac{3^6.2^{21}}{2^{17}.3^9}=\frac{16}{27}\)

Answer 2

\(\frac{^{9^3}.^{^{8^7}}}{^{ }6^9.^{ }16^9}=\frac{729.2097152}{10077696.256}=\frac{1528823808}{2579890176}=\frac{16}{27}\)

Answer 3

\(\frac{9^3.8^7}{6^9.16^2}=\frac{\left(3^2\right)^3.\left(2^3\right)^7}{\left(2.3\right)^9.\left(2^4\right)^2}=\frac{3^6.2^{21}}{2^9.3^9.2^8}\) \(=\frac{2^{12}}{3^3.2^8}=\frac{2^4}{3^3}=\frac{16}{27}\)