Question

các bạn có thể giải hộ mình bài này ko?

Tìm x,biết:

\(\frac{2}{\left(x+2\right)\left(x+4\right)}+\frac{4}{\left(x+4\right)\left(x+6\right)}+\frac{6}{\left(x+8\right)\left(x+14\right)}=\frac{x}{\left(x+2\right)\left(x+14\right)}\)

Answer 1

=> \(\frac{1}{x+2}-\frac{1}{x+14}=\frac{1}{16}\)

=> \(\frac{x+14}{\left(x+2\right).\left(x+14\right)}-\frac{x+2}{\left(x+2\right).\left(x+14\right)}=\frac{1}{16}\)

=> \(\frac{\left(x+14\right)-\left(x+2\right)}{\left(x+2\right).\left(x+14\right)}=\frac{1}{16}\)

=> \(\frac{x+14-x-2}{x\left(2+14\right)}=\frac{1}{16}\)

=> \(\frac{12}{16x}=\frac{1}{16}\)

=> x = 12

Answer 2

tui gặp rồi nhưng tử giống nhau