a) \(\frac{3}{4}x+1=2\)
\(\Leftrightarrow\)\(\frac{3}{4}x=1\)
\(\Leftrightarrow\)\(x=\frac{4}{3}\)
b) \(\frac{2}{3}+\frac{1}{3}:x=-1\)
\(\Leftrightarrow\)\(\frac{1}{3}:x=-\frac{5}{3}\)
\(\Leftrightarrow\)\(x=-\frac{1}{5}\)
c) \(\left|2x+1\right|=5\)
\(\Leftrightarrow\left[\begin{array}{nghiempt}2x-1=5\\2x-1=-5\end{array}\right.\)
\(\Leftrightarrow\left[\begin{array}{nghiempt}2x=6\\2x=-4\end{array}\right.\)
\(\Leftrightarrow\left[\begin{array}{nghiempt}x=3\\x=-2\end{array}\right.\)
A/ \(\frac{3}{4}\)x+1=2 \(\Rightarrow\)\(\frac{3}{4}x=2-1\Rightarrow\frac{3}{4}x=1\Rightarrow x=1:\frac{3}{4}\Rightarrow x=\frac{4}{3}\)
Vậy x=...
B/ \(\frac{2}{3}\)+\(\frac{1}{3}\):x=−1 \(\Rightarrow\frac{1}{3}:x=-1-\frac{2}{3}\Rightarrow\frac{1}{3}:x=\frac{-5}{3}\Rightarrow x=\frac{1}{3}:\frac{-5}{3}\Rightarrow x=\frac{-1}{5}\)
C, |2x-1|=5
\(\Rightarrow2x-1=5\) hoặc \(2x-1=-5\)
Ta Xét các TH
Th1: 2x-1=5 \(\Rightarrow2x=6\) \(\Rightarrow x=3\)
TH2 2x-1=-5 \(\Rightarrow2x=-4\Rightarrow x=-2\)
Vậy x=-2 hoặc x= 3