\(A+2HCl-->ACl_2+H_2\)
a,
\(n_{H_2}=\frac{3,36}{22,4}=015\left(mol\right)\)
\(n_A=n_{H_2}=0,15\left(mol\right)\)
\(\Rightarrow M_A=\frac{3,6}{0,15}=24\left(g\right)\)
\(\Rightarrow\)A là Magie(Mg)
b,
\(Mg+2HCl-->MgCl_2+H_2\)
\(n_{HCl}=\frac{14,6}{36,5}=0,4\left(mol\right)\)
Mg HCl
\(\frac{0,15}{1}\) < \(\frac{0,4}{2}\)
\(\Rightarrow\)HCl dư
\(n_{HCl}pứ=2n_{Mg}=0,3\left(mol\right)\)
\(n_{HCl}dư=0,4-0,3=0,1\left(mol\right)\)
\(n_{MgCl_2}=n_{Mg}=0,15\left(mol\right)\)
\(n_{H_2}=n_{Mg}=0,15\left(mol\right)\)
\(\Rightarrow m_{HCl}dư=0,1.36,5=3,65\left(g\right)\)
\(\Rightarrow m_{MgCl_2}=0,15.95=14,25\left(g\right)\)
\(\Rightarrow m_{H_2}=0,15.2=0.3\left(g\right)\)
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