Question

Bài toán :

Tìm x \(\left(x-2\right)^2-x\left(2x-3\right)+\left(x-5\right)\left(x-3\right)=16\)

Answer 1

\(\left(x-2\right)^2-x\left(2x-3\right)+\left(x-5\right)\left(x-3\right)=x^2-4x+4-2x^2+3x+x^2-8x+15=\left(x^2-2x^2+x^2\right)-\left(4x-3x+8x\right)+\left(4+15\right)=0-9x+19=0\Leftrightarrow9x=19\Leftrightarrow x=\frac{19}{9}\)

Answer 2

Lời giải:
\((x-2)^2-x(2x-3)+(x-5)(x-3)=16\)

\(\Leftrightarrow x^2-4x+4-(2x^2-3x)+(x^2-8x+15)=16\)

\(\Leftrightarrow (x^2-2x^2+x^2)-4x+3x-8x+4+15=16\)

\(\Leftrightarrow -9x+19=16\)

\(\Leftrightarrow -9x=16-19=-3\Rightarrow x=\frac{-3}{-9}=\frac{1}{3}\)

Answer 3

\(-9x+19=16\Leftrightarrow-9x=-3\Leftrightarrow x=\frac{1}{3}\)