Question

Bài 35 ạ

Answer 1

35.B

 \(Fe+2HCl\rightarrow FeCl_2+H_2\\ a\)

\(Mg+2HCl\rightarrow MgCl_2+H_2\\ b\)

\(n_{H_2}=\dfrac{11.2}{22.4}=0.5\)

Ta có hệ: \(\left\{{}\begin{matrix}56a+24b=20\\a+b=0.25\end{matrix}\right.\)\(\Leftrightarrow\left\{{}\begin{matrix}a=0.25\\b=0.25\end{matrix}\right.\)

\(m_{FeCl_2}=0.25\cdot\left(56+35.5\cdot2\right)=31.75g\\ m_{MgCl_2}=0.25\cdot\left(24+35.5\cdot2\right)=23.75g\)

\(m_{muối}=31.75+23.75=55.5g\)