\(n_{CuO}=\dfrac{160}{80}=2\left(mol\right)\)
PTHH: 2Cu + O2 --to--> 2CuO
2 <---- 1 <-------- 2
\(\rightarrow\left\{{}\begin{matrix}V_{O_2}=1.22,4=22,4\left(l\right)\\m_{Cu}=2.64=128\left(g\right)\end{matrix}\right.\)
nCuO=160/80=2mol
2Cu+O2→(to)2CuO
2 1 2 ( mol )
a)VH2=1.22,4=22,4l
b)mCu=2.64=128g
\(n_{CuO}=\dfrac{m}{M}=\dfrac{160}{80}=2\left(mol\right)\)
\(PTHH:2Cu+O_2\underrightarrow{t^o}2CuO\)
\(a,\)\(n_{O_2}=n_{CuO}:2=1\left(mol\right)\)
\(\rightarrow V_{O_2}=n.22,4=1.22,4=22,4\left(l\right)\)
\(b,n_{Cu}=n_{O_2}.2=1.2=2\left(mol\right)\)
\(\rightarrow m_{Cu}=n.M=2.64=128\left(g\right)\)
