Question

Bài 1:Tính

\(\frac{\frac{1}{3}-\frac{4}{5}}{\frac{1}{3}+\frac{4}{5}}.\frac{\frac{3}{4}-\frac{5}{3}}{\frac{3}{4}+\frac{5}{3}}:\frac{\frac{4}{5}-1}{1-\frac{2}{3}}\)

Answer 1

\(\dfrac{\dfrac{1}{3}-\dfrac{4}{5}}{\dfrac{1}{3}+\dfrac{4}{5}}.\dfrac{\dfrac{3}{4}-\dfrac{5}{3}}{\dfrac{3}{4}+\dfrac{5}{3}}:\dfrac{\dfrac{4}{5}-1}{1-\dfrac{2}{3}}\)

\(=\dfrac{\dfrac{-7}{15}}{\dfrac{17}{15}}.\dfrac{-\dfrac{11}{12}}{\dfrac{29}{12}}:\dfrac{\dfrac{-1}{5}}{\dfrac{1}{3}}\)

\(=\dfrac{-7}{17}.\dfrac{-11}{29}:\left(-\dfrac{3}{5}\right)\)

\(=\dfrac{77}{493}:\left(-\dfrac{3}{5}\right)\)

\(=-\dfrac{385}{1479}\)

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