Bài 1: Tính
\(N=\left(\dfrac{1}{4.9}+\dfrac{1}{9.14}+\dfrac{1}{14.19}+...+\dfrac{1}{44.49}\right).\dfrac{1-3-5-7-...-9}{89}\)
Bài 2 : Rút gọn
a) A = |2x + 4,6| - 2x + 15,4
b) B = |x + 7,2| - |x - 1,2|
c) C = 8,5x - 19, 5 - |1,5x + 4,5|
d) D = 8,5 + x - |8,5 - x|
Bài 3 : Tìm x và y \(\in\) N.Biết 25 - y2 = 8(x - 2009)2
Bài 4 ; Cho :
\(A=\left(\dfrac{1}{2^2}-1\right)\left(\dfrac{1}{3^2}-1\right)\left(\dfrac{1}{4^2}-1\right)...\left(\dfrac{1}{100^2}-1\right)\)
So sánh phân số sau vs \(\dfrac{-1}{2}\)
Bài 1 :
Sửa để : \(N=\left(\dfrac{1}{4.9}+\dfrac{1}{9.14}+\dfrac{1}{14.19}+....+\dfrac{1}{44.49}\right)\cdot\dfrac{1-3-5-7-..-49}{89}\)
\(N=\dfrac{1}{5}\cdot\left(\dfrac{1}{4}-\dfrac{1}{9}+\dfrac{1}{9}-\dfrac{1}{14}+\dfrac{1}{14}-\dfrac{1}{19}+...+\dfrac{1}{44}-\dfrac{1}{49}\right)\cdot\dfrac{1-\left(3+5+7+..+49\right)}{89}\)
\(N=\dfrac{1}{5}\cdot\left(\dfrac{1}{4}-\dfrac{1}{49}\right)\cdot\dfrac{1-624}{89}\)
\(N=\dfrac{1}{5}\cdot\dfrac{45}{196}\cdot\dfrac{-623}{89}\)
\(\Rightarrow N=\dfrac{9}{196}\cdot-7=\dfrac{-9}{28}\)
